How to Solve Some JAMB UTME Physics Past Questions

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For all candidates writing JAMB physics, this page provides answers to some UTME physics past questions.

Question 1

Which of the following consists entirely vector quantities? {UTME 2001}
A. Work, pressure and moment B. Velocity, magnetic flux and reaction.
C. Displacement, impulse and power. D. Tension, magnetic flux and mass.

Solution

Vector quantities has both magnitude and direction

Option A – pressure and work are scalar quantities

Option B – they are all vector quantities

Option C- power is a scalar quantity

Option D – mass is a scalar quantity

B is the correct option

Question 2

A plane sound wave of frequency 85.5Hz and velocity 342ms-1 is reflected from a vertical wall. At what distance
from the wall does the wave have an antinode?{UTME 2001}
A. 0. 1m B 1m C. 2m D. 3m

Solution

V =fℷ

ℷ = V/f = 342/85.5 = 4 m

distance to have an antinode = ℷ/4 = 4/4 = 1m

B is the correct option

Question 3

A string is fastened tightly between two walls 24cm apart. The wavelength of the second overtone is{UTME 2001}
A. 12cm B. 24cm C. 8cm D. 16cm

Solution

third harmonic is the second overtone

second overtone = ℷ/2 + ℷ/2 +ℷ/2 = 3ℷ/2

3ℷ/2 = 24

ℷ = 16 cm

D is the correct option

Question 4

Find the frequencies of the first three harmonics of a piano string of length 1.5m, if the velocity of the waves on the
string is 120ms-1.{UTME 2001}
A. 180Hz, 360Hz, 540Hz. B. 360Hz, 180Hz, 90Hz.
C. 40Hz, 80Hz, 120Hz. D. 80Hz, 160Hz, 240Hz.

Solution

first harmonic = F0 = v/2l = 120/2*1.5 = 120/3 = 40Hz

second harmonic = 2f0 = 2*40 = 80Hz

third harmonic = 3f0 = 3*40 = 120Hz

C is the correct option

Question 5

A gas with initial volume 2 x 10-6m3 is allowed to expand to six times its initial volume at constant pressure of
2 x 105Nm-2. The work done is{UTME 2001}
A. 4.0J B. 12.0J C. 2.0J D. 1.2J

Solution

workdone = pdv

dv =V2 – V1 = (6*2 x 10-6) – 2 x 10-6

dv = 12 x 10-6 – 2 x 10-6 = 10 x 10-6

workdone = 2 x 10^5 * 10 x 10-6 = 20 x 10^-1 = 2.0J

C is the correct answer

Question 6

The process of energy production in the sun is{UTME 2001}
A. radioactive decay B. electron collision.
C. Nuclear fission. D. Nuclear fusion

Solution

The answer is Nuclear Fusion

D is the correct option

Question 7

A student is at a height 4m above the ground during a thunderstorm. Given that the potential difference between
the thunderstorm and the ground is 107V, the electric field created by the storm is {JAMB Physics 2001}
A. 2.0 x 106NC-1. B. 4.0 x 107NC-1.
C. 1.0 x 107NC-1. D. 2.5 x 106NC-1

Solution

E = V/d = 10^7 / 4 = 2.5 x 10^6

D is the correct option

Question 8

An object is weighed at different locations on the earth. What will be the right observation? {JAMB Physics 2010}
A. Both the mass and weight vary B. The weight is constant while the mass varies
C. The mass is constant while the weight varies D. Both the mass and weight are constant.

Solution

The mass of an object doesnt change but weight changes because the force of gravity varies from place to place on the surface of earth.There are two reasons behind this variation:
The shape of earth and the rotation of the earth.

C is the correct option

Question 9

In a hydraulic press, the pump piston exerts a pressure of 100 Pa on the liquid. What force is exerted in the second piston of cross-sectional area 3m2?{UTME 2010}
A. 200 N B. 100 N C. 150 N D. 300 N

Solution

Pressure = Force /Area

100 = force/3

force exerted = 300 N

D is the correct answer

Question 10

If the angle between two vectors P and Q is 0 degree, the vectors are said to
A. be perpendicular B. be parallel C. interest at angle 60o. D. intersect at angle 45o. (UTME 2004)

Solution

The angle between two parallel lines is zero, therefore, B is the correct option

Question 11

What happens to the rays in a parallel beam of light?
A. They diverge as they travel. B. They meet at infinity. C. They intersect D. They converge as they travel. (UTME 2004)

Solution

Parallel beam of light meet at infinity

B is the correct option

Question 12

The process whereby a liquid turns spontaneously into vapour is called
A. boiling B. evaporation C. sublimation D. relegation. (UTME 2005)

Solution

Solid to gas is sublimation

liquid to vapour at all temperature is evaporation

liquid to vapour at a fixed temperature is boiling

Since the word spontaneous is used in the question which means occur without having been planned, therefore, evaporation is the best answer.

B is the correct option

More solutions to JAMB Physics Past questions

Question 1

The energy of a photon having a wavelength of 10^-10m is {utme 2013}
A. 1.7 x 10-12J B. 2.0 x 10-15J C. 1.7 x 10-13J D. 2.0 x 10-12J

Solution

E = hf = hc/λ

h is the planck’s constant = 6.63 × 10–34 J s

c is the speed of light = 3 x10^8

λ is the wavelength

E = (6.63 × 10–34 * 3 x 10^8)/10^-10

E = 19.89 x 10^-16 = 1.989 x 10^-15 = 2 x 10^-15 J

B is the correct answer

Question 2

The bond between silicon and germanium is{utme 2013}
A. ionic B. dative C. covalent D. trivalent

Solution

The bond is covalent. C is the correct option

Question 3

If a current of 2.5A flows through an electrolyte for 3 hours and 1.8g of a substance is deposited, what is the mass of the substance that will be deposited if a current of 4A flows through it for 4.8 hours?{UTME 2013}
A. 4.8g B. 2.4g C. 3.2g D. 4.2g E. 4.6g

Solution

M = ZIt

Z = M / It = 1.8 /2.5*3 = 0.24 g/Ah

Z is electrochemical equivalence and it is a constant

If the current and the time changes

M = 0.24*4*4.8 = 4.6g

E is the correct option

Question 4

An electric device is rated 2000W, 250V. Calculate the maximum current it can take.{utme 2013}
A. 6A B. 9A C. 8A D. 7A

Solution

P = Iv

2000 = 250*I

I = 2000/250

I = 8A

C is the correct option

Question 5

A house has ten 40W and five 100W bulbs. How much will it cost the owner of the house to keep them lit for 10 hours if the cost of a unit is N5?{utme2013}

A. N20 B. N90 C. N50 D. N45

Solution

Total power = 10*40 + 5*100 = 900W =0.9kw

Energy =power x time(hour)= 0.9*10 =9kwh

1kwh = N5

9kwh = N5 *9 = N45

D is the correct answer

Question 6

Calculate the force acting on an electron of charge 1.5 x 10-19C placed in an electric field of intensity 105Vm-1.{utme 2013}
A. 1.5 x 10-14N B. 1.5 x 10-11N C. 1.5 x 10-12N D. 1.5 x 10-13N

Solution

Electric field intensity = force / charge

10^5 = force/1.5 x 10^-19

force = 1.5 x 10^-19 * 10^5 = 1.5 x 10^-14 N

A is the correct option

Solution 7

A man 1.5m tall is standing 3m in front of a pinhole camera whose distance between the hole and the screen is 0.1m.
What is the height of the image of the man on the screen?{utme 2013}
A. 1.00m B. 0.05m C. 0.15m D. 0.30m

Solution

Image distance/object distance = image height/object height

0.1/3 = image height / 1.5

image height = 1.5*0.1 /3 = 0.05 m

B is the correct option

Question 8

Two liquids X and Y having the same mass are supplied with the same quantity of heat. If the temperature rise in X is twice that of Y, the ratio of specific heat capacity of X to that of Y is{utme 2013}
A. 1 : 4 B. 2 : 1 C. 1 : 2 D. 4 : 1

Solution

mxcxQx = mycyQy

mx = my

Qx = 2Qy

cx*2Qy = cyQy

cx/cy = 2/1 = 2:1

B is the correct option

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